Discussion 2024 Round 9: Teams & In Game Discussion

Rowsus

Rowsus

Statistician
#346
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#346
If you are picking a playing fixture with 8 teams playing each other, there are more than 28 ways any individual Round can structure up.
28 would be the number of picking 2 teams at random to play each other.
Start with team 1. They have 7 potential opponents. That leaves 6 teams. Pick any of the 6 at random, and they have 5 potential opponents.
That leaves 4 teams.
These 4 teams can only make 3 structures:
A v B, C v D
A v C, B v D
A v D, B v C
7 x 5 x 3 = 105 ways to structure the Round.
Number of ways 1 to 4 can structure to play 5 to 8.
Team 1 can have 4 opponents.
Team 2 can have 3
Team 3 can have 2
Leaving Team 4 with 1.
4 x 3 x 2 x 1 = 24.

24/105 = 22.9%

Happy to have myself corrected, if I've got this wrong.
 
Juzzo

Juzzo

#349
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AFL Club
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#349
Rowsus said:
If you are picking a playing fixture with 8 teams playing each other, there are more than 28 ways any individual Round can structure up.
28 would be the number of picking 2 teams at random to play each other.
Start with team 1. They have 7 potential opponents. That leaves 6 teams. Pick any of the 6 at random, and they have 5 potential opponents.
That leaves 4 teams.
These 4 teams can only make 3 structures:
A v B, C v D
A v C, B v D
A v D, B v C
7 x 5 x 3 = 105 ways to structure the Round.
Number of ways 1 to 4 can structure to play 5 to 8.
Team 1 can have 4 opponents.
Team 2 can have 3
Team 3 can have 2
Leaving Team 4 with 1.
4 x 3 x 2 x 1 = 24.

24/105 = 22.9%

Happy to have myself corrected, if I've got this wrong.
Click to expand...
Thanks for your time, i liked doing these problems year's ago at school, but am way out of touch now, thanks again.
 
Peter56

Peter56

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AFL Club
Essendon
#353
Rowsus said:
If you are picking a playing fixture with 8 teams playing each other, there are more than 28 ways any individual Round can structure up.
28 would be the number of picking 2 teams at random to play each other.
Start with team 1. They have 7 potential opponents. That leaves 6 teams. Pick any of the 6 at random, and they have 5 potential opponents.
That leaves 4 teams.
These 4 teams can only make 3 structures:
A v B, C v D
A v C, B v D
A v D, B v C
7 x 5 x 3 = 105 ways to structure the Round.
Number of ways 1 to 4 can structure to play 5 to 8.
Team 1 can have 4 opponents.
Team 2 can have 3
Team 3 can have 2
Leaving Team 4 with 1.
4 x 3 x 2 x 1 = 24.

24/105 = 22.9%

Happy to have myself corrected, if I've got this wrong.
Click to expand...
Beyond me. I will believe you 🙂
 
Creeker

Creeker

#355
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#355
toxic said:
Sadly yes

It seems the humour / sarcasm ability on a Friday night has been totally lost on the board 2nite
Click to expand...
Hmmm. Seems the Geelong players are trying to re-create the inner Joel Selwood vibe when he used to back on the ground with the bandaged head.
7 Cats players wearing Hair/head bands. It's not working. What is going on in that town ? Looks ridiculous.
Sweet also in my team. :)
 
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