As I'm a maths nerd, let's take a purely mathematical approach to this.
We'll make some assumptions, just for the point of the exercise.
Let's look at 2 Coaches.
Coach A is G'n'R all the way. He also doesn't mind paying top dollar, for what he assumes is quality.
He starts a 12-0-18 (12 Prem, 0 Midpricers, 18 Rookie) team, and has Gawndy. His Prem structure is 3.4.2.3
Coach B is a value hunter. He has Gawndy, but likes taking a risk. He shops for value, and only has a few top dollar picks.
He starts a 11-4-15, and has a Prem/Midprice structure of 4.5.2.4
Coach A picks his Prems from the top 8 priced Defs/Fwds + top 10 priced Mids. He has Gawndy.
If Coach A wrote down all the Prem structures possible from those picks, he'd have:
56 x 210 x 1 x 56 = 658,560 different Prem structures to pick from. A really difficult task, but at least they are players with good recent history.
Coach B picks his Prems from the top 12 priced Def/Mids (he's looking for some value!) + top 15 priced Mids. He has Gawndy.
Coach B now needs to find his 4 Midpricers he's going to punt on. He picks 4 players from the 334 players priced from $280k to $450k.
Coach B got his computer to print out all the possible Prem/Midpricer teams he had to choose from. It came to:
495 x 3,003 x 1 x 495 x 509,267,001 = 37,472,000,000,000,000
Coach B faints, and says "No way!"
I'll pick my Midpricers from these 8 players (what are the chances he's got all the right Midricers in there?!)
Coach B cranks the computer up, and prints out the teams again.
He now has:
495 x 3,003 x 1 x 495 x 70 = 5,150,000,000 teams to choose from.
While some will correctly argue, that you can reduce both Coach A and Coach B's choices down, by eleminating injured players, interrupted preseasons etc, it is still very indicative.
Coach A has 658,560 teams to choose from.
Coach B, even if he has the right 8 Midpricers, has 5,150,000,000 teams to choose from.
That's 78,000 times more teams.
Who do you think has the greater possibility of success?